# Gen Chem II – Lec 6 – Crystal Lattices of Solid Structures

♫ ‘Blue Hawaii’ ♫

by Alicia Tibbitt [ukulele playing] Leeward Community College

has a beautiful view of Pearl Harbor. I’m standing on the balcony

here at the college, and in the background you can see

several decomissioned military ships that are slowly being stripped

for their parts. We call that the ship graveyard,

here at the college. Those ships are reminiscent

of a time not forgotton, especially for some of the old-timers

here on the island of O’ahu. Because, on December 7, 1941,

Japanese airplanes invaded this island, and those same beautiful waters

were then a fiery inferno. On that day,

order was broken in our country. And for those old timers,

that day is remembered. For me, today, the view is a serene one. And I often come out to this balcony to talk on the phone with my family

back in Virginia, or to read my Bible. Sometimes I may even come out here

to escape students who are knocking at my office door, in order to prepare

for the next class lecture. In today’s lecture, we focus

on the established order of solids in their crystalline form. And I think you’ll find this lecture

quite interesting today. Crystals can be beautiful objects

to percieve. And their structure, often times, contains

many interesting geometrical features. And looking at a crystal

can be a quite captivating experience. But to the scientific mind,

it’s no surprise that this outward expression

of beauty and geometry is a reflection of the internal ordering that’s occurring

among the particles that form the crystal. I’m holding here a piece of quartz crystal

that was lent to me by Roger Kwok, who’s a professor of science

here at Leeward Community College. Roger also lent several other crystals

for this lecture, that I’ll show you here in just a moment. Today we delve into the realm of solids

in their crystalline form, which is the most naturally occurring form

for a solid to be in. Some solids are amorphous,

meaning their structure has no order. The particles are frozen

in whatever configuration they happen to be in

at the time the solid forms. Glass is an example, where the particles

that form the glass have no order in them. However, most solids are crystalline

in nature, meaning the particles that form the solid

have a certain ordering that exists among them. And today we will study crystals

by looking at that order, by focusing in on what is the arrangement

of particles that form the crystal, or form the solid. So to start off, let’s first define what a crystal is

and see how one is formed. A solid is crystalline

when the particles it is composed of possess a certain internal order,

called the crystal lattice. Crystals form, over time, when the forces of interaction

cause the particles to align properly. Conditions need to be just right, and…they have to exist

for a long period of time. And when you have conditions that remain constant

for a long period of time, the pressure and the temperature

remain relatively constant then the forces of interaction

that exist between the particles are also remaining relatively constant. And given enough time, the forces will guide the particles

right into place, perfectly. And that keeps on happening,

basically, off into infinity, or until the crystal runs out of room. So given enough time, the right conditions,

and the right types of particles, a crystal will, basically, form. So there are lots of situations

where conditions remain constant over long periods of time,

with the right types of particles. And that can occur deep within caverns

within the Earth, and so on. So, because there are many types

of conditions out there, that are constant,

and many types of particles as well, you will find lots of different types

of crystals that form in nature. One way to classify crystals

is by the particles from which it is composed. And many crystals are composed of atoms. There are copper crystals out there. And I do have a piece of copper crystal,

that I’ll show you here up close. Now, the structure of this copper crystal

is not as geometrical as the quartz crystal that I showed you a moment ago. But this is crystalline, none the less. The particles do have a certain order

among them, that you would see if you were to break out

your atomic-level magnifying glass. Silver and gold

also come in crystalline form. Now, this gold wedding ring,

which symbolizes the covenant that I made with my beautiful wife, Alicia,

is actually not crystalline gold. This gold has been heated up

and cooled down many times over, and that ordering in the particles,

that crystal lattice, has long since been removed. But if you were to go out

into a cave somewhere and discover a piece of gold up there

in the wall of the cave, not only would you be quite lucky, but you would see gold

in its crystalline form. And you would see that jaggedness

on the surface of the gold. Many crystals are formed from molecules. And you’ve doubt seen water

in its crystalline form, because that’s ice. You’ve probably seen carbon dioxide

in its crystalline form, which is dry ice. In fact, in our previous lecture

we discussed some differences between water and carbon dioxide

with the help of phase diagrams. Silicon dioxide, which is

that quartz crystal that I showed you. I’ll show you that one again

up a little bit more closely. Beautiful geometric features in the quartz. So here’s another piece of quartz

little bit smaller. You’ve also probably seen C 12 H 22 O 11,

because that’s sucrose, or table sugar. And when you were a kid,

you may have even made rock candy, which is a very large sucrose crystal. Sulfur comes in a molecular form

as S 8 molecules, 8 sulfur atoms attached together

in the shape of a ring. And these ring-shaped molecules

are the particles that form the crystal. I do have a piece of sulfur crystal here. You can find sulfur crystals near volcanos. Beautiful yellow crystal. You can probably see

some of the geometric features in the sulfur crystal. Many crystals are composed of ions. And you’ve also probably seen

sodium chloride, which is table salt, but in the crystal community,

it’s known as halite. You’ve…may have seen calcium carbonate,

which is calcite. Calcite forms these really nice crystals. And I’ll show you a piece

of calcite right here. An almost perfect piece of calcite,

where the edges, or the faces are almost perfect parallelograms. Now this piece of calcite

was actually cleaved, meaning it came from a larger rock,

and that rock was struck, with a hammer or something,

and this is the piece that came off. So very interesting

how you can strike a rock and have something like this break off. Calcium fluoride, or fluorite,

forms these nice green crystals, and I’ll show you a piece of fluorite. If you look closely, you might be able to see

some box-shaped…portions of this crystal. It’s like a bunch of boxes

that are stuck together. Really nice-looking green crystal. And my favorite up here

is iron sulfide, or pyrite. Pyrite forms these nice

cubical-shaped crystals. Very metallic looking.

An almost perfect cube of pyrite here. Now pyrite is also known as fool’s gold. And whereas this

is a more perfect piece of pyrite, it probably had a lot of time to form,

that’s why it formed so perfectly, if you see a less perfect piece of pyrite,

it might look like this. And maybe you can see some of those cubes

kind of stuck together. So, this is known as fool’s gold,

and if you were to see a piece like this on the wall of a cave, you might

mistakenly think you’ve struck it rich. So there are many different types

of crystals out there, some of them are quite beautiful. They contain certain features in common. And the most common feature

is that the particles have a certain order among them called the crystal lattice. Now, the various crystals

contain different crystal lattices, but by studying one particular type

of crystal lattice we’ll be able to understand something

about all of them. And I’ve drawn here

a representative lattice for you to see. What the lattice is an arrangement

of particles in 3-dimensional space, and it’s a repeating pattern of units. So, here is a lattice, which shows

a repeating pattern that occurs over and over and over again,

basically off into 3-dimensional space. And the unit that’s being repeated here

is the shape of a box, or a cube. So, I’ve drawn here actually 27 cubes, stacked 3 cubes tall, 3 cubes wide

and 3 cubes thick. And I’ve taken one out,

kind of zoomed it up for you to get a better look at it. You can see the particle at each

of the eight corners of the cube. Now many crystals

do take on the cubic lattice, and have a smallest repeating unit,

or unit cell, which is in the shape of a cube. It might not be a big surprise

that that piece of pyrite here is formed from that cubic lattice. And if you were to break out

your atomic-level magnifying glass, you would see the particles…

in the shape of a cube, or basically arranged in a cubic form, which is repeated

over and over and over again. Now, it might be more of a surprise, but that copper is also formed

from a cubic lattice. Not as obvious here as it is right here. So sometimes the large shape

of the crystal reflects exactly the small shape of the unit cell

from which the crystal is composed of. But other times it’s not as obvious. Another crystal that is formed

from the cubic lattice is that piece of fluorite right here. So, you can probably see

some of the cubic features in the fluorite. This sulfur that I showed you is formed from a closely related

type of lattice, which is composed

of these box-shaped unit cells stacked over and over and over again. So, little bit closely related to the cube,

but not quite a perfect cube. The piece of calcite

that I showed you right here, it’s very interesting that that calcite

is formed from a lattice that is composed of this shape,

which is called the rhomb. So it’s almost an identical shape, it actually is identical

to the large shape of the crystal. This rhomb right here is the same unit cell

from which quartz is composed of, but not as obvious here

as it is for the calcite. So all crystals

have their own crystal lattice, which is composed from a certain unit cell. And the way we’re gonna study crystals

is by focusing on one type of lattice and one type of unit cell,

which the simplest type, also probably the most interesting type,

which is the cubic unit cell. So, before we do that,

let’s first take a look at how crystals are studied,

how this crystal lattice is observed, and that’s by X-ray crystallography. The structure of a crystal lattice

can be found by X-ray crystallography. In this method, passing an X-ray beam

through a crystal creates an interference pattern

on the other side of the crystal. And this interference pattern is based

on the particle positions within the crystal. So, to see how this method works, and to understand

what an interference pattern is, let’s first examine the interference pattern

for ocean waves that are hitting the shore. Suppose you have a set of ocean waves

that are traveling towards shore, and they hit some wall that has

a couple of holes in the wall, that are separated by some distance. And further, suppose that the separation

of the holes is comparable in size to the wavelength

of waves that are hitting the shore. Now, what happens, is at each hole, another wave is emanated on the other side

of the hole in a circular fashion. And this is a well-known phenomenon. You can see this happen all the time

if you study ocean waves. So, if you have a circular wave emanating

from this hole, and another one from that hole

at the same time, then these two circular waves will interact

with eachother at certain locations in the water,

and they’ll kind of double-up and create a really tall wave. That’s called constructive interference. Well, at other locations in the water

the waves will sort of cancel off, and the water will be flat,

and that’s called destructive interference. So if you observe this situation

from some further location, you will see that interference pattern, where the waves will constructively interfere

and destructively interfere. And that interference pattern

can be studied and used to predict the separation of the two holes

from where the waves first emanated from. So just by looking

at the interference pattern, you can predict how far the holes

were separated from one another. Well, that’s exactly what is done

in X-ray crystallography. In X-ray crystallography,

you have a source of X-rays, which are really high-energy light waves. And the wavelength of X-rays

are comparable to the size of an atom or a molecule or particle within a crystal. So what you do is you shoot

a beam of X-rays, which are a bunch of light waves,

traveling at the same time, and you pass that through a crystal. And these X-ray waves interact

with the particles in the crystal, and are then deflected. And on the other side of the crystal, all of those deflected X-rays

will interact with eachother, and will also generate

an interference pattern. And you call this a defraction pattern. And that defraction pattern

can be collected and studied and used to determine the positions

of the particles that are in the crystal. And, many crystals have been studied

by X-ray crystallography, and many crystal lattices have been solved. And so those crystal lattices,

being built up by their small unit cell, we have found many types of unit cells

that occur within the different crystal lattices

out there. And so I’ve drawn several examples

of unit cells. Here is a cubic unit cell,

where all of the edge lengths are equal, and it’s all right angles. So many particles are found to take on

the cubic arrangement in crystals. Other crystals have their particles

arranged in a sort-of elongated box, called the orthorhomb. Another boxy type of unit cell

is the tetragonal arrangement. But there are various unit cells

that are not boxy in shape. One example is the rhombohedral arrangement, which is actually the same arrangement

as that piece of cleaved calcite that I showed you in the previous slide. So, in this lecture, we’ll focus

on one type of lattice, the one that’s built up

from the cubic unit cell. In the cubic lattice system particles arrangement can be divided

into three main classes, primitive, also known as simple,

face-centered and body-centered. In this discussion, the particles

that we’re working with are atoms. It’s much easier to deal with atoms

versus molecules because an atom is a spherical object. The primitive lattice, or simple,

cubic lattice is taken on by the element polonium. And this lattice is represented right here

in this 2-dimensional rendition, where the particles are circles. And you can see the particles

are lined up perfectly. This line right here is exactly lined up

with that line and that line and the following line, and you can imagine

this going off into all directions. The 3-dimensional system

will have particles coming out of the board and particles going back

into the board as well. But you can get a good understanding

of this system by looking at the 2-dimensional lattice. Now one thing you might notice

is that these particles in this line are not packed in very well

with the particles in the adjoining lines. They’re not fitting in to the crevices

of the next line over. So it’s not a very efficient way

to pack particles. And you would describe that

by the packing efficiency. The packing efficiency

of the primitive lattice is only 52%. So in the 3-dimensional space,

occupied by a primitive crystal lattice, only 52% of that space is actually occupied

by particles. The other 48% is empty space,

which is the crevices between the particles. Now, the coordination number

in this lattice is six. And what the coordination number is, is how many other particles each one

is in contact with. So if you look at, say,

this particle right here and you ask, ‘How many other particles

is it in contact with?’. Well, in this single 2-dimensional layer

you can count four other particles. But in three dimensions,

there’s gonna be one more particle coming out of the board

that it’s in contact with, and one more particle going back

into the board. So this particle is actually in contact

with six other particles. Coorination number 6. And since every particle

has an identical environment, the coordination number is 6 for all

of the particles. So it’s a property of the lattice,

in general. Now…this lattice can be divided up

into individual repeating unit cells. And one way to draw the unit cell

is as follows. The unit cells in this 2-dimensional

lattice are represented as squares. And you can see that the square starts

from the beginning of this particle, and it goes over to the middle

of that particle. So, this square can be repeated

over and over and over again, and all of the squares look the exact same. So this is a valid unit cell. Now, to get a better understanding

of the 3-dimensional unit cell, I’ve popped this one out

into 3 dimensions for you. And you can see the front face

of this 3-dimensional cubic unit cell looks the exact same

as that 2-dimensional one, where the face goes

right through the middle of these front four particles. Now in the 3-dimensional unit cell,

you have… another set of four particles

behind these front four particles. And so, there’s actually eight particles

that are in contact with this single unit cell. Now you might ask, inside this unit cell,

‘How many particles are there?’. Well, the answer there is the equivalent

of one particle. Now that might be kind of difficult to see, because you don’t see an entire particle

inside this box. What you see are eight pieces of a particle

inside the box. And so, what do those pieces add up to? Well the answer is they add up

to the equivalent of one particle. And to better see that,

I’ve drawn four unit cells here, where a particle has been immersed

into those four unit cells. So one half of this blue particle

is immersed into those four unit cells, and the other half of the blue particle

is immersed into the upper four unit cells that are not drawn. So, if this particle is sitting

right at the corner of these four lower unit cells, then what fraction of the particle

is inside this cell right here? Well the answer is 1/8 of the particle. Anytime you have a particle that’s centered

at a corner, 1/8 of the particle is inside the box and the other 7/8 of the particle

are in the other 7 adjoining unit cells. So here, where you have this particle

that’s sitting, centered right at this corner, 1/8 of the particle is actually

inside this box, and the other 7/8

are in the other 7 unit cells that are in contact at that corner. And so, this corner,

1/8 of the particle is inside the box. And the other corners also have

1/8 of the particle inside the same box. So since there are eight corners,

you can count them all up, eight eighths, means the equivalent of one particle

completely inside this unit cell. Now, you can ask, ‘How long is this edge length,

l, of the unit cell?’. Well it’s pretty simple to determine that

for the primitive system. You can see that the edge length

is twice the radius. Because going form this corner,

which is at the center of this particle, over to that corner,

which is at the center of the next particle you pass through two radii. So, the edge-length is ‘2r’ here. Now, the simple, or primitive, system,

is kind of a weak lattice, because there’s not a lot

of particle-particle contact here. The efficiency is pretty low,

and so because there’s not a lot of particle-particle contact,

the coordination is only six, it’s a pretty easy lattice to break up. Other crystal lattices have

a higher coordination number, and more particle-particle contact,

and are therefore stronger. If you take a look

at the face-centered lattice, this is actually the most efficient way

to pack particles. And…the face-centered lattice

is taken on by several elements, gold and aluminum included. I’ve drawn here three layers

of the face-centered lattice. The pink particles are in the back,

the yellow particles are in the middle, and the blue particles are furthest out

of the board. Now these particles are

all of the same type — they’re just color-coded to help us see

which ones are which. So I think you’ll get

the best understanding by focusing on the yellow particles that are

in the middle layer. Now there are also 16 yellow particles

drawn here, just like there are 16 particles

drawn over there. But these yellow particles,

whereas they’re all lined up right here, these four particles are fitting

into the crevices of the particles in the next line,

which are fitting into the crevices of the particles in the next line.

And so the lines are sort of staggered. And these yellow particles cannot be packed

together any more tightly than they are. So this yellow layer

is the most efficient way to pack those yellow particle. And similarly, the pink particles

in the layer behind that are also packed in the most efficient…manner as well.

Identical staggering in the pink particles. And the blue particles as well.

I’ve only drawn a few blue particles. If you wanted to add more blue particles

in this outer layer, you would put one right here over this hole

that is formed between the yellow particles and the pink particles behind it. Put one right over that hole.

One over this hole. This one. And that one. So these blue particles are placed

over the holes that are formed between the yellow and the pink particles

behind the yellow ones. Now there’s actually another way

that the blue particles can be placed on top of the yellow layer. And instead of putting them over the holes,

they could have been placed over… the pink particles,

directly on top of the pink particles, so, the blue particles could have placed,

instead of right here, it could have been placed,

here, here and here. And then again

right there, there and there. Now that would have also been

an efficient way to pack the blue particles together right on top

of the yellow particles. But if you did that,

the blue particles would be lined up perfectly with all of the pink particles, and you wouldn’t be able to see

the pink particles behind that. And that type of lattice is actually

not a cubic lattice. There is no way to draw a cubic unit cell

with that arrangement, even though it’s also a very close way

to pack particles, it’s a different type of lattice. This type of lattice,

is a cubic arrangement. And in order to see

the actual cubic unit cell, which is rather difficult…

I’ve done my best here. Now this cubic unit cell

has been color-coded as well, [background noise]

and you can see this blue particle has been drawn right there. These six yellow particles,

along the white triangle, are drawn right here,

one, two, three, four, five, six. And then the pink particles,

this one, this one and that one, are actually,

this, this and that one right there. Now…the face-centered unit cell

is somewhat different than the primitive unit cell. You still have a particle at each

of the eight corners. But in addition to that, you also have

a particle located at each of the six faces. Now when a particle is at a face,

one half of the particle is inside the box, and the other half is outside the box. And you can see that by looking

at this little drawing that shows a particle, sitting right on a face, centered on a face. Half of it is inside this unit cell

and half of it is in the other unit cell that’s not drawn. Now… how many atoms are inside

are inside this face-centered unit cell? Well, the answer is four. And the way you can determine that

is by looking at the eight corners. Eight corners, and in each corner,

1/8 of the particle is inside the box, so that is one particle inside the box. But then you have six faces, and at each face you have one half

of the particle in the box. So that’s six halves as well.

So eight eighths and six halves add up to the equivalent of four particles

inside this unit cell. Now…the packing efficiency

for the face-centered lattice is a lot greater

than the primitive lattice. This is the maximum packing efficiency

for packing particles, and it’s 74%. So, there’s a lot of

particle-particle contact here. And the coordination number is actually 12. So you remember

what the coordination number is. It’s how many other particles

each one is in contact with. So one way see the coordination number is to look at maybe one

of these yellow particles. And you can see that this yellow particle is touching six other yellow particles

in the same layer. So how many particles is it touching

in the layer behind it? Well, it’s touching the other three

pink particles in the layer behind it. And then, in the layer in front of it,

it would be touching three blue particles. So, the coordination number

of this one is 12. And you could see that each yellow particle

would be touching three blue particles in the layer in front. So a coordination number of 12 means

a lot of particle-particle contact. So this is a rather strong lattice. Now, the edge length

of the face-centered crystal lattice is a little more complicated to get to

than the primitive lattice. The length of the edge of this box

is actually 2 times root 2 times the atomic radius. So, it’s no longer twice the radius

because there’s a space between these two corner particles.

So it’s more than twice the radius. And the way you can find the edge length

is to draw a triangle from one corner all the way

to the other corner and then back. So if you look at this triangle right here, this is the edge length ‘l’,

that is the edge length ‘l’ and the length of the diagonal

is four times the radius — it’s going right through these atoms,

so it’s four times the radius. So I’ve taken this triangle,

and I’ve put it right there. So you have an edge length,

the same edge length, and then four times the radius. And because this is a right triangle,

you can use the Pythagorean theorem to solve for ‘l’,

and when you solve for ‘l’, it turns out that ‘l’

is 2 times root 2 times ‘r’. So, the last type of cubic unit cell,

or cubic arrangement, is the body-centered cubic, which is taken on by elements

molybdenum and barium. And the body-centered arrangement

is more obviously a cubic arrangement, as opposed to the face-centered arrangement. The body-centered arrangement,

we can see that the particles sort of line up in squares. Now, what you have here

in the body-centered arrangement is you have one layer staggered relative

to the other layer. So the staggering kind of alternates

back and forth. You can imagine these white particles

that are in the layer behind, there would be another equivalent layer

directly in front of these clear particles, that would kind of line up

with the white particles. So, the packing efficiency

in the body-centered cubic is 68%, which is in the middle of the primitive

and face-centered. The coordination number for body-centered

arrangement is eight. And this is rather easy to see, I think. Because if you look at one particle,

say this white one right here, it’s in contact

with these four clear particles in front, and another four particles

in the equivalent layer behind it. So a coordination number of eight

for all of the particles. Now, I’ve drawn here several unit cells,

represented by squares, and if we pop one out, you can see

the four clear particles right here. And then the white particle behind it. And then the other four clear particles

are behind that. So again, in this unit cell, you have

a particle at each of the eight corners, but now you have one

completely inside the box. So if you add up all of those portions

of particles as well as the one inside the box,

you get the equivalent of two particles inside this unit cell. So, the edge length

of the body-center unit cell is more complicated than the face-centered. The edge length turns out to be 4 times

the radius over the square root of 3. Now, rather than show you the derivation,

I think it’s a good exercise if you go ahead and derive this yourself. So, in order to do that,

you’ll wanna find the the triangle that needs to be drawn, and again,

you’ll use the Pythagorean theorem. But what triangle are you going to use? It’s not the same one that you would use

for the face-centered lattice. So try to find that triangle,

and go ahead and derive this formula for the edge length,

in terms of the atomic radius. The groundwork that we just laid out

on the cubic crystal lattices will allow us to predict certain properties,

which crystallize in those lattices. And the properties that we’ll be examining

are the intensive properties, meaning they do not depend

on how much material. So, for an intensive property,

it’s the same whether you have this much material, or that much. An example is the density. So the density of a substance

doesn’t depend on how much material. The density is the same

as if it’s that much versus that much, versus even a tiny unit cell’s worth

of material. And that’s the approach

that we’ll be taking, is to focus in on just a unit cell. And the property of that unit cell

will be the same as the property of the large material, in general. So, the first example asks us to find

the fraction of empty space in the body-centered cubic lattice. Now the fraction of empty space is closely

related to the packing efficiency. You remember the packing efficiency,

which is 68% for the body-centered lattice, is the percentage of filled space

within the lattice. Now, if the percentage of filled space

in the body-centered cubic lattice is 68%, then the percentage of empty space in the body-centered cubic lattice

would be 32%. So, if you convert that percentage

of empty space to fraction of empty space, we should expect about 0.32

for the fraction of empty space. So let’s see what we get. We can calculate the fraction

of empty space, as 1 minus the fraction of filled space. The fractions add up to 1. So if you take 1 minus

the fraction of filled space, and the fraction of filled space

would be the volume of the atoms inside the unit cell,

divided by the volume of the unit cell. So that the fraction of filled space

in the unit cell. So 1 minus the fraction of filled space

would be the fraction of empty space. Now, we can rewrite this fraction — 1 minus the volume of the atoms

would be the volume of 1 atom, which is 4/3 times π r cubed,

where r is the atomic radius, times 2, because there are 2 atoms

in the BCC unit cell. So, the volume of the atoms

in the BCC unit cell divided by the entire volume of the cell,

which is the edge length cubed. And you remember,

for the body-centered cubic unit cell, the edge length is

4r over square root of 3. So this right here is the expression,

and if you reduce it on down, there will be a lot of cancellation occur.

The r cubed will cancel off, and some other stuff

will cancel off as well. You’ll be left with 1 minus square root of 3

times π divided by 8. So if you calculate this, it’s

1 minus 0.68, which is where that 68% comes from,

and a bunch more decimal places. And so you end up with

0.3198252384… So you can continue this on

if you prefer, because all of these digits

are significant. That’s because all of these numbers that you use to calculate it

are exact numbers. So quite a lot of significant figures,

as many as you need. The next example. Gold crystallizes

in the face-centered cubic… arrangement, or lattice,

and has an atomic radius of 1.44 angstroms. Find the density.

So density is another intensive property. Now, we’ll just calculate the density

of the unit cell, and that will be the same

as the density of gold. So the density of the unit cell

will be the mass inside the unit cell divided by the volume of the unit cell. So the mass inside the unit cell

will be the mass of four atoms, because there are four atoms

inside a face-centered cubic unit cell. So the way you calculate

the mass of four atoms is as follows. We know for gold, the atomic mass is

196.98 grams per mole. So, you can convert this to grams per atom

by the following conversion factor, 1 mole is Avogadro’s number of atoms,

so the moles cancel off, and you’ll be left with grams per atom, then when you multiply by 4 atoms,

you get grams up here in the top. So that’s how many total grams

are in one unit cell. And you divide by the volume.

For the face-centered cubic unit cell, the volume of this cell

is the edge length cubed, which is 2 times root 2 times r,

all cubed. And if you plug that in,

2 times root 2 times the atomic radius, 1.44 angstroms…

now we’ll convert that atomic radius to centimeters, 100 centimeters is the same

as 10 to the 10 power angstroms. So the angstroms cancels,

and then you have 2 times the square root of 2

times the atomic radius (in centimeters), all cubed. And if you do this calculation,

you get 19.3346 grams per centimeter cubed, but it’s a 3 sig fig number

because of the atomic radius, and so it’s 19.3 grams per centimeter cubed. Now if you want to compare this

to the density of water, which is 1 gram per centimeter cubed,

you can see this is more than 19 times heavier than the water.

Gold’s quite heavy. The last example. Polonium crystallizes

in the primitive lattice, and has a density

of 9.196 grams per centimeter cubed. Find the atomic radius of polonium. Now the equation that we’ll be using

is very similar to the previous equation in example 2,

because we’re given the density and asked to find the radius here,

whereas in the previous example, we were given the radius

and asked to find the density. So the equation will be very similar —

we’ll just be working backwards. And if you want to compare the two,

you’ll notice very few differences. The only differences are in the value

for the density, this is unknown,

and we know the density here, the atomic mass for polonium

is 209 grams per mole. And there’s only one atom in the unit cell

of the primitive lattice. And in the denominator,

the volume is the edge length cubed, but the edge length for the primitive

lattice is 2 times the radius. So here, the radius is the unknown.

And with the same conversion factor, if we solve for the radius,

we’ll get the answer in angstroms. So doing that, we calculate 1.20 angstroms

for polonium, which is close to the known value. So it’s very interesting how we

can calculate these intensive properties, or use the intensive properties

to calculate certain atomic properties, with just the knowledge

of the crystal lattice. I hope you have enjoyed this lecture.

I have really enjoyed putting it together. And this does close up the first phase

of our course on phases of matter. In the next portion of our course,

we’ll start to cover solutions. So in the next several lectures,

we’ll get into various aspects of solutions. So I hope you join me for that.

Aloha. ♫ ‘Blue Hawaii’ ♫

by Alicia Tibbitt ♫ Night and you, ♫ ♫ in blue Hawaii, ♫ ♫ the night is heavenly… ♫

On Lecture 6, example 3, Find the radius of Po you have r=1.20A. I got 1.67A.

very good video! Congratulations! Perfect explain!

splendid lecture professor …….you have good presentation skill…………..watching from Bhopal, India

Awesome lecture Dr. Tibbit. Why do I even go to class haha. Pura Vida 😉

one of the best lecture and a lecturer ever i have seen !!! Wonderful Sir ! your drawings and they way of your teaching is really simple and attractive 🙂 good luck for the future programs.

Whoaa "4 Aliens" Found ALIVE & they just disliked this awesome Video..!!

Perfect video….. Simple and best!

♥ from India 😀

you are excellent in your teaching,,, you devotes

a great amount of personal effort .taught systematically ,clearing fundamentals,

thanks … to visualise sodid crystals

pls pls pls pls pls make a advance video on this topic

Really it is a great effort

he deserve more subscribe

nice lec sir. thank you very much….

i have a problem i want to let know how could we determine formula of ionic compounds from diagram of lattice structure plz if any one know the answer tell me

Beautiful work. Thank you for your contribution to my education. Awesome diagrams and relation to nature.

you are fantastic

I'm a sailor and chem student, and I support this video.

You are amazing I am so glad I found your videos!! You put so much effort into it and explain them perfectly

wow thank you so much thats my best lec ever …….all e way from Zimbabwe

Do you draw your boards yourself? They look really good.

Thank you sooo much sir !!!!!

Love from Indore,India

Thanks a lot for this great lecture.

it's amazing . thank-you from india

FCC is ABCABC, HCP is ABAB, what kind of arrenge is BCC?

Thanks for making this informative video.

Thank you,Can anyone use the crystal lattice to analyze the stocks charts' waves? someone wrote that the waves of the stocks' charts are having similarity with crystal lattice.

This is amazing…Thank you from Nigeria

Really impressive video!

Ex3: R = 1.67A